0=b^2-62b+385

Solution for 0=b^2-62b+385 equation:

0=b^2-62b+385

We move all terms to the left:

0-(b^2-62b+385)=0

We add all the numbers together, and all the variables

-(b^2-62b+385)=0

We get rid of parentheses

-b^2+62b-385=0

We add all the numbers together, and all the variables

-1b^2+62b-385=0

a = -1; b = 62; c = -385;
Δ = b2-4ac
Δ = 622-4·(-1)·(-385)
Δ = 2304
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2304}=48$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(62)-48}{2*-1}=\frac{-110}{-2}
=+55
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(62)+48}{2*-1}=\frac{-14}{-2}
=+7
$